[Greasemonkey] generating XPath string from dom node

[Jonathan Buchanan]

Further to Matt's suggestion, if you want to select a specific
element, you'll need the offset for the case where there are multiple
elements with the same path. Something like:

function createXPath(el)
{
    // Path to element
    var tagNames = [el.tagName];
    var parent = el.parentNode;
    while (parent.nodeType == 1)
    {
        tagNames.push(parent.tagName);
        parent = parent.parentNode;
    }

    // Element offset
    var offset = 0;
    var sibling = el.previousSibling;
    while (sibling)
    {
        if (sibling.tagName == el.tagName)
        {
            offset++;
        }
        sibling = sibling.previousSibling;
    }

    return "//" + tagNames.reverse().join("/") + "[" + offset + "]";
}

Jonathan.

On 3/16/06, Matt Labrum <darktempler at gmail.com> wrote:
>      function createxPath(e){
>
>      var nodes = Array(e.tagName);
>      parent = e.parentNode;
>
>      while(parent){
>
>      nodes[nodes.length] = parent.tagName;
>
>      parent = parent.parentNode;
>
>      }
>
>      nodes = nodes.reverse();
>      var xpath = '//';
>      for(var i=0;i<nodes .length;i++){
>      if(typeof(nodes[i])=='undefined')continue;
>      xpath += nodes[i] + '/';
>      }
>
>      xpath = xpath.substr(0,xpath.length-1);
>      return xpath;
>
>      }
>
> On 3/16/06, Al <anevare1 at yahoo.com> wrote:
> >
> > Is there a simple technique for obtaining the XPath expression for a
> > clicked-on html dom node?   Something similar to the way Platypus creates an
> > XPath to a right-clicked element when it stores a user script.  Thanks for
> > your suggestions.  Al
> >
> >
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